ONB Type II, why?
Why do we need to use two field elements from two different field to generate a Type II ONB?
First pick an element of order in to find in field .
Why?
Why do we need to use two field elements from two different field to generate a Type II ONB?
First pick an element of order in to find in field .
Why?
Still in the middle writing the papers, now got stuck on choosing the curve that works with polynomial, ONB Type I and Type II.
For example, referring to Rosing’s book, the poly_prime 155bits is not really a prime polynomial, while the field size available for both Type I and II is 148bits. 155bits only for Type II.
Then after a curve has been choosed, I still have to make a code to convert that from polynomial basis to ONB I and II.
When will it be finished? Grrrrr 😦
Still trying to finish one paper and got stuck on how to compare the performance of one basis with another.
Space complexity? Time complexity? Execution time?
[Big headache.]
Don’t forget to report (and document) progress (or lack of? 🙂 )
Have spent a week thinking about this and finally got the answers after had some discussions 🙂
Now move on to plaintext embedding algorithms.
see…see… temen berantem as a sparring is greatly needed 😀
Basis conversion can be done easier with matrix 🙂
Answering #2 from list of questions here:
An ONB of Type I exists a given field if:
A Type II optimal normal basis exists in if:
Interesting notes:
An ONB exists in for 23% of all possible values of
said this paper. Hmmm, that’s something.
Apparently converting from one basis to another like from polynomial to normal basis is not as easy as I thought, hmm… have spent days scribbling, thinking, frustated, madly curious, and end up browsing several papers about that and being succesfully diverted from the main target of doing paper on plaintext embedding, oh my!
Let me digest some more papers I have just downloaded 30secs ago, and will post something useful here as soon as possible 😉
[big headache continues…]
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Again, from here:
1. How to convert from polynomial to normal bases?
Answer:
GF element can be represented in Polynomial Basis (PB) or Normal Basis (NB).
For example we have polynomial
The PB representation in is
If be a field with elements and an element of it such that elements are linearly dependent. Then this set forms a normal basis for
The NB representation of elements in will only use 3 elemens , dan .
Mike 5:46 pm on March 1, 2009 Permalink |
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